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Evaluate $\sum_{n=1}^{20}3^{n-2}$
in Mathematics by Diamond (60,604 points) | 29 views

1 Answer

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T1= 1/3

T2= 1

T3= 3

T4= 9

common ratio= 1/(1/3) = 3/1 = 3

Sum20 = a(r^n -1)/(r-1)

            = 1/3 x  (3^20 -1)/(3-1)

               = 581 130 733.33
by Diamond (42,256 points)

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