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The two diagrams below represent a metalrod with an initial leangth $L_{1}$ which is then stretched (elongated) to a length $L_{2}$

The strain measure $(\epsilon)$ is defined as a ratio of elongation with respect to the original length and is given by the formula:

$$ \epsilon = \dfrac{L_{2}-L_{1}}{L_{1}}$$

  1. Express $L_{1}$ as the subject of the formula.
  2. Hence, or otherwise, calculate the value of $L_{1}$ if $\epsilon=0.8$ and $L_{2}=18$ cm
  3. Convert the value obtained in 2 to a binary number.
in Mathematics by Diamond (62,028 points) | 20 views

1 Answer

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1. eL1 = L2 - L1

    eL1 + L1 = L2

         L1(e + 1) = L2

          L1 = L2/(e + 1)

2. L1 = 18/(0.8 + 1)

        = 10 cm

3. 10 = 8 + 2 = 2^3 + 2

        = 1010
by Diamond (42,434 points)

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