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A father is four times as old as his son. In six years time their combined ages will be 57. How old is the father now?
in Mathematics by Diamond (66,722 points) | 69 views

1 Answer

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let x=father's age, y=son's age

x=4y

and in 6 years time, (xt6)+(y+6)=57, then solve simultaneous equations

x=4y and x+y+12=57

4y+y+12=57

5y =45

x=9

y=9/4

age ratio is 4:1, 4/5 x 45 =  36 years old for father and 45-36= 9 years old for son
by Diamond (42,934 points)

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