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Help me find the value(s) of $x$ in $-4x^{2} + 1 \geq 0$

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Help me find the value(s) of $x$ in $-4x^{2} + 1 \geq 0$
in Mathematics by ♦ Diamond (60,890 points) | 47 views

1 Answer

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(-2x+1)(2x+1)>0 c.v -2x+1 =0 or 2x+1 =0 x=1/2. x=-1/2 therefore x< 1/2 or x> -1/2

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DEAR guys Please add great of equal,I didn't because my media can't do such
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