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Please help with these simultaneous equations

$$ y = 2x - 2 $$

$$2x^{2} = 2 -y^{2}$$
in Mathematics by Diamond (67,402 points) | 26 views

1 Answer

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substituting 1 into 2

2x^2 = 2-(2x -2)^2

 3x^2 -4x +1=0

 (3x-1)(x-1)=0

      x= 1/3 or 1

then y= 2(1/3) -2= -1 1/3 or -1.33

        or y= 2(1) -2= 0
by Diamond (42,982 points)

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