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(5^2x-1)/(5^x+1)=4
in Mathematics by Wooden (218 points)
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| 41 views

1 Answer

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Use laws of exponents with base 5: 5^(2x-1)-(x+1)=4 5^x-2=4 (x-2)log5=log4 xlog5=2log5+log4 x=log(5^2)(4)/log5 x=log100/log 5 = 2.86 (2.d.p)
by Wooden (172 points)

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