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arrow_back A student drops a piece of apparatus with a mass of 5kg from a height of 2m to the floor. What is the change of potential energy?

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A student drops a piece of apparatus with a mass of 5kg from a height of 2m to the floor. What is the change of potential energy?

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A student drops a piece of apparatus with a mass of 5kg from a height of 2m to the floor. What is the change of potential energy?

\(U = m \times g \times h \)

where

\(U\) is the Potential Energy

\(m\) is the mass

\(g = 10ms^{-2} \) is the acceleration due to gravity

and \(h\) is the height above the ground

 

So in this case,

\[U = 5kg \times 10ms^{-2} \times 2m = 100kgm^2s^{-2} = 100J\]
by Platinum
(104,456 points)

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