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A swimmer attempts to cross a river at 6 m/s but the current is flowing downstream at 2 m/s.  What is the swimmer’s resultant velocity?
in Physics by Diamond (74,100 points)
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2 Answers

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x   =$\sqrt{40}$

x    =6.32ms^-1
by Wooden (610 points)
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x^2 = y^2+z^2

x^2 = (6)^2+(2)^2

x^2 =36+4

x^2 = 40

x = $\sqrt {40}$

x    =6.32ms^-1
by Wooden (1,276 points)

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