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- In quadrilateral $ABCD$, it is given that $AB = BC = 4 \text{cm}, \angle{ABC} = 100^{\circ}$ , and $\angle{CDA} = 130^{\circ}$ . Find the length of $BD$.
- $A(-2;-5), B,C, $ and $D$ are the vertices of quadrilateral $ABCD$ such that diagonal $AC$ is perpendicular to diagonal $BD$ at $T$. The equation of $BTD$ is given $2y+x=18$ and $AB=15$units
- Find the length of segment $BD$.
- C, a point on the x-axis, A(-5; -3) and B(4;12) are the vertices of a triangle. AB intersects the x-axis at E. $A\hat{B}C = \theta$ and $B\hat{E}C = \alpha$
- In the diagram, A(-2;3), C(10,11) and D(5,-1) are the vertices of $\bigtriangleup{ACD}$. CA intersects the y-axis in F and CA produced cuts the x-axis in G. The straight line DE is drawn parallel to CA. $C\hat{F}O=\alpha$

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