Institutions: Global | TUT | UCT | UJ | UZ | Wits

+1 vote
9 views
Solve the equation $x^2+3x+4=0$
| 9 views

+1 vote

Use the quadratic formula to solve this equation.

Remember that the standard form of a quadratic equation is $ax^2 + bx+c=0$

So, $a=1, b=3$ and $c=4$

$$x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}$$

Now substituting for $a,b$ and $c$, we have:

$$x=\frac{-3\pm\sqrt{(-3)^2-4\cdot 1 \cdot 4}}{2\cdot 1}$$

Simplifying gives us,

$$x=\frac{-3\pm\sqrt{-7}}{2}$$

Because the discriminant is negative, we do not have real solutions.

by Wooden (2,212 points)
selected by