MathsGee Answers is Zero-Rated (You do not need data to access) on: Telkom | Dimension Data | Rain | MWEB
First time here? Checkout the FAQs!
x
MathsGee is Zero-Rated (You do not need data to access) on: Telkom |Dimension Data | Rain | MWEB

1 like 0 dislike
136 views
A 20,000 kg train makes a turn of 50 meters at a velocity of 40 m/s.  Determine the centripetal force of the train.
in Physics by Diamond (74,874 points)
recategorized by | 136 views

4 Answers

1 like 0 dislike
F=?    M= 20000 kg    A= 40 m/s    R= 50m

F = MV^2/r

F = 20000 x (40)^2/ 50

F =    20000 x 1600 / 50

F = 640 000N
by Wooden (1,276 points)
0 like 0 dislike
f=ma

f=20.000x40

f=800N
by Wooden (424 points)
0 0
Please recheck formula because a distance is involved
0 like 0 dislike
m =20000kg r = 50m v = 40m/s F =? F = mv^2/r =20000(40)^2/50 = 640,000N
by Wooden (516 points)
0 like 0 dislike
F= mv^2/r m=20,000kg ,r= 50m and v=40m/s

F= 20000,40^2/50

=640,000 N
by Wooden (1,084 points)

MathsGee provides answers to subject-specific educational questions for improved outcomes.



On MathsGee Answers, you can:


1. Ask questions
2. Answer questions
3. Comment on Answers
4. Vote on Questions and Answers
5. Donate to your favourite users

MathsGee Tools

Math Worksheet Generator

Math Algebra Solver

Trigonometry Simulations

Vectors Simulations

Matrix Arithmetic Simulations

Matrix Transformations Simulations

Quadratic Equations Simulations

Probability & Statistics Simulations

PHET Simulations

Visual Statistics

ZeroEd Search Engine

Other Tools

MathsGee ZOOM | eBook