# arrow_back Suppose we know the voltage is 12 V, and the resistance is 3 Ω. What is the current?

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Suppose we know the voltage is 12 V, and the resistance is 3 &Omega;. What is the current?

4 Amperes

Explanation

$$V = IR$$

$$12 = 3 \times I$$

divide throughout by $3$ so as to isolate the $I$

$\dfrac{12}{3}=\dfrac{12}{3}I$

remember that anything divided by itself is 1, so:

$\dfrac{12}{3}=1 \times I$

and $$\dfrac{12}{3}=4$$, so

$$I = 4 A$$

The circuit has a current of 4 amperes

by Platinum
(119,120 points)

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