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If 2 => 6, 3 =>12, 4 => 20, 5 => 30, 6 => 42 then 9 => ?
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10

Explanation

As you can see, with each successive term, $a=>b$, a is multiplied by a number 1 bigger than the previous one like this:

$2 \times 3 => 6$

$3 \times 4 =>12$

$4 \times 5 => 20$

$5 \times 6 => 30$

$6 \times 7 => 42$

$7 \times 8 => 56$

$8 \times 9 => 72$

$9 \times 10 => 90$ - therefore answer is $10$

by Diamond (75,450 points)

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