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What is the current in the bulb it has resistance ${15}{\Omega}$?
in Physics & Chemistry by Platinum (122,212 points)
recategorized by | 200 views

2 Answers

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The formula for current is I = V/R

Thus one can only calculate the ampere if one has the voltage and resistance. The information provided is not sufficient.
by Wooden Status (884 points)
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0 Ampere, Current doesn't flow in a closed-loop circuit when there is no voltage! Potential difference excites electrons and thus creates currents in a closed-loop circuit.
by Wooden Status (3,038 points)

winkinterestingly though they haven't specified if it a closed-loop or not and theoretical or formula wise current is inversely proportional to the resistance thus I= 1/15 R????? Clarify Mr. Edzai

Related questions

If \(R_{1}=2 \Omega, R_{2}=4 \Omega, R_{3}=6 \Omega\), determine the electric current that flows in the circuit below. In the circuit below, the battery has an internal resistance $r$ and an emf $\varepsilon$. A variable resistor $R$ is connected in the circuit and the ammeter and voltmeter register readings.
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1 answer
In the circult diagram below, the battery has nogligible internal resistance. The resistance of the ammeter and wires may also be ignored

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