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What is the voltage across an LED if its resistance is ${6.5}{\Omega}$ whan a current of ${200}{mA}$ flows?
in Physics by Diamond (67,402 points)
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Best answer
V=IR

= 200x6.5/1000

=1.3volts
by Wooden (1,084 points)
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V = IR

=200*10^-3 X 6.5

= 1.3 V
by Wooden (518 points)
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R = 6.5 Ω

I = 200mA = 200/1000 = 0.2A

V = ?

V = IR

    = (0.2)(6.5)

    = 1.3V
by Wooden (926 points)

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