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The base of a right pyramid is a rectangle of length $80 \mathrm{~cm}$ and width $60 \mathrm{~cm}$.
Each slant edge of the pyramid is $130 \mathrm{~cm}$. Calculate the volume of the pyramid.
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\begin{array}{l}
\text { Height } \mathrm{h}=\sqrt{130^{2}-50^{2}}\\
=120 \mathrm{~cm}\\
\text { Volume }=1 / 3 \times 80 \times 60 \times 120\\
192000 \mathrm{~cm}^{2}
\end{array}
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