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1. Complete the following statement: If $\mathrm{A}$ and $\mathrm{B}$ are two mutually exclusive events, then $\mathrm{P}(\mathrm{A}$ and $\mathrm{B})=\ldots$
2. Given that $\mathrm{A}$ and $\mathrm{B}$ are mutually exclusive events. The probability that event $A$ occurs is $0,55 .$ The probability that event $B$ does not occur is $0,7$. Calculate $\mathrm{P}(\mathrm{A}$ or $\mathrm{B})$.
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Solution1

$P(A \cap B)=0$ i.e. $P(A \text{and} B)=0$

Solution 2

$P(B)=1-P\left(B^{\prime}\right)$
$=1-0,7$
$=0,3$
$P($ A or $/$ of $B)=P(A)+P(B)$
$\quad=0,55+0,3$
$=0,85$

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