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If one root of the equation $x^{2}+p x+12=0$ is 4, while the equation $x^{2}+p x+q=0$ has equal roots, then the value of ' $q$ ' is

1) $\frac{49}{4}$
2) 4
3) 3
4) 12
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(1)

Explanation

Since 4 is one of the root of $x^{2}+p x+12=0$ $\Rightarrow 16+4 p+12=0 \Rightarrow p=-7$

and equation $x^{2}+p x+q=0$ has equal roots $\Rightarrow D=49-4 \mathrm{q}=0 \Rightarrow q=\frac{49}{4}$

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