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Factorize $x^{3}+4 x^{2}+3 x+12$
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$x^{3}+4 x^{2}+3 x+12$

$=\left[\mathrm{x}^{3}+4 \mathrm{x}^{2}\right]+[3 \mathrm{x}+12]$

Common factor in $x^{3}+4 x^{2}$ is $x^{2}$ and common factor in $3 x+12$ is 3 . These can be factored as:

$=x^{2}(x+4)+3(x+4)$

$=(x+4)\left(x^{2}+3\right)$
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