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Factorize $8 x^{2}-10 x-3$
in Mathematics by Gold Status (10,273 points) | 9 views

1 Answer

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We need to find two numbers such that their product is $-24$ and their sum is $-10$. Let's find the factors of $-24$.


Our desire numbers are $-12$ and 2 .


We will now re-write our trinomial: $8 x^{2}-12 x+2 x-3$


$=\left[8 x^{2}-12 x\right]+[2 x-3]$


$=4 x(2 x-3)+1(2 x-3)$


$=(4 x+1)(2 x-3)$

by Gold Status (10,273 points)

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