1 like 0 dislike
263 views

Suppose $\mathrm{ABCD}$ is a square with side length $(x-1) \mathrm{cm}$. If the area of rectangle $\mathrm{ABFE}$ is $\left(x^{2}+x-2\right) \mathrm{cm}^{2}$, then the length of $\mathrm{FC}$, in $\mathrm{cm}$, is

(A) 2
(B) 3
(C) 4
(D) 5

| 263 views

0 like 0 dislike
0 like 0 dislike
0 like 0 dislike
0 like 1 dislike
1 like 0 dislike
1 like 0 dislike
0 like 0 dislike
0 like 0 dislike
0 like 0 dislike