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Normalize the vector $v=(1,-3,4,2)$
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Given that $v=(1,-3,4,2)$ then its norm is $\|v\|=\sqrt{1+9+16+4}=\sqrt{30}$

Since $v$ is not a unit vector, we can normalize it as follows:

$$\hat{v}=\frac{v}{\|v\|}=\left(\frac{1}{\sqrt{30}}, \frac{-3}{\sqrt{30}}, \frac{4}{\sqrt{30}}, \frac{2}{\sqrt{30}}\right)$$
This is the unique unit vector in the same direction as $v$.
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