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Let $A$ and $B$ be two square invertible matrices of the same order. Then $\left((A B)^{T}\right)^{-1}$ is equal to

A) $\left(B^{T}\right)^{-1}\left(A^{T}\right)^{-1}$

B) $\left(B^{-1}\right)^{T}\left(A^{-1}\right)^{T}$

C) $B^{-1} A^{-1}$

D) $B^{T} A^{T}$

E) none of the above
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