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Evaluate \(1,6 \times 10^{-19} \times 3,2 \times 10^{-19} \div 5 \times 10^{-21}\)
in Mathematics by Platinum (130,882 points)
reopened by | 110 views

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Step 1: Carry out the multiplication
For multiplication and division the exponents do not need to be the same. For multiplication we add the exponents and multiply the \(N\) terms:
\[
1,6 \times 10^{-19} \times 3,2 \times 10^{-19}=(1,6 \times 3,2) \times 10^{-19+(-19)}=5,12 \times 10^{-38}
\]
Step 2: Carry out the division
For division we subtract the exponents and divide the \(N\) terms. Using our result from the previous step we get:
\[
5,12 \times 10^{-38} \div 5 \times 10^{-21}=(5,12 \div 5) \times 10^{-38-(-21)}=1,024 \times 10^{-17}
\]
Step 3: Write the final answer
The answer is: \(1,024 \times 10^{-17}\)
by Platinum (130,882 points)
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