arrow_back Determine $D_{x}\left(\frac{x^{3}+3 x^{2}+6 x+8}{x+2}\right)$

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Determine
$D_{x}\left(\frac{x^{3}+3 x^{2}+6 x+8}{x+2}\right)$

\begin{aligned} &\frac{x^{3}+3 x^{2}+6 x+8}{x+2} \\ &=\frac{(x+2)\left(x^{2}+x+4\right)}{x+2} \\ &=x^{2}+x+4 \end{aligned}
\begin{aligned} &D_{x}\left(x^{2}+x+4\right) \\ &=2 x+1 \end{aligned}
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