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Find the common ratio of the geometric sequence $1,3,9,27, \ldots$ Then express each sequence in the form $a_{n}=a_{1} r^{n-1}$ and find the eighth term of the sequence.
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$\text { Since } r=\frac{a_{2}}{a_{1}}=\frac{3}{1}=3$
Then $a_{n}=1\left(3^{n-1}\right)$
Therefore, the eighth term of the sequence is
\begin{aligned} a_{8} &=1\left(3^{8-1}\right) \\ &=1\left(3^{7}\right) \\ &=2187 \end{aligned}
by Diamond (55,153 points)

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