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An electronic device makes a beep after every 60 seconds. Another device makes a beep after every 62 seconds. They beeped together at $10 \mathrm{a} \cdot \mathrm{m}$. At what time will they beep together at the earliest?
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Given :
Beep Duration of first device $=60$ seconds
Beep Duration of Second device $=62$ seconds
To find the interval of beeping together, we need to find the LCM of 60 and 62 first.
$60=2 \times 2 \times 3 \times 5$ $62=2 \times 31$ LCM $=2 \times 2 \times 3 \times 5 \times 31=1860$ seconds
Convert time into min
$160 \mathrm{sec}=\frac{1860}{60} \mathrm{mins}=31 \mathrm{~min}$
electronic devices will beep after very 31 minutes.
hence, both device will together again beep at $10: 31$ am again.
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