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Without actual division, show that each of the following rational number is a terminating decimal. Express in decimal form: $\dfrac{23}{\left(2^{3} \times 5^{2}\right)}$.
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Clearly either 2 or 5 is not factor of 23 , so given fraction is in its simplest form.
Also, the given fraction already in the form of $\left(2^{\mathrm{m}} \times 5^{\mathrm{n}}\right)$.
Hence, the given rational is a terminating decimal.
We can written it as:
$\dfrac{23}{\left(2^{3} \times 5^{2}\right)}=\dfrac{23}{200}=0.115$, which is the decimal form.
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