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Light is refracted at the boundary between water and an unknown medium. If the angle of incidence is $25^{\circ}$, and the angle of refraction is $20,6^{\circ}$, calculate the refractive index of the unknown medium.
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The angle of incidence $\theta_{1}=25^{\circ}$
The angle of refraction $\theta_{2}=20,6^{\circ}$
$n_{1}=1,333$
We need to calculate the refractive index for the unknown medium.

We can use Snell's law to calculate the unknown refractive index, $n_{2}$
According to Snell's Law:
\begin{aligned} n_{1} \sin \theta_{1} &=n_{2} \sin \theta_{2} \\ n_{2} &=\frac{n_{1} \sin \theta_{1}}{\sin \theta_{2}} \\ n_{2} &=\frac{1,333 \sin 25^{\circ}}{\sin 20,6^{\circ}} \\ n_{2} &=1,6 \end{aligned}

Typically glass has a refractive index between 1,5 to 1,9 . Therefore the unknown medium is typical glass.
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