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Find the first 5 terms of the sequence defined by the formula $u_{n}=3 n+6$.
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$u_{1}=3 \times 1+6=9$ $u_{2}=3 \times 2+6=12$ $u_{3}=3 \times 3+6=15$ $u_{4}=3 \times 4+6=18$ $u_{5}=3 \times 5+6=21$ So the sequence is $9,12,15,18,21, \ldots$
Note that the terms of the sequence increase by 3 each time and that the formula contains a ' $3 n$ '.
by Diamond (44,715 points)

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