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Which number(s) is(are) equal to the quarter of its (their) square?
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If $x$ is the number to find, then the quarter of its square is $(1 / 4) x^{2}$.
$x$ is equal to the quarter of its square hence: $x=(1 / 4) x^{2}$
First write the above equation with its right side equal to zero.
$x-(1 / 4) x^{2}=0$
$x(1-(1 / 4) x)=0$, factor $x$ out
solutions: $x=0$ and $x=4$

1) $x=0$, quarter of its square is $(1 / 4) 0^{2}=0$. Hence $x$ and the quarter of its square are equal.

2) $x=4$, the quarter of its square is $(1 / 4) 4^{2}=4$. Hence $x$ and the quarter of its square ar. equal.
by Platinum (130,878 points)

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