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Which number(s) is(are) equal to half its (their) square?
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Let $x$ be the number to find. Half its square is $(1 / 2) x^{2}$.
$x$ is equal to half its square hence: $x=(1 / 2) x^{2}$
First write with right side equal to zero.
\begin{aligned} &x-(1 / 2) x^{2}=0 \\ &x(1-(1 / 2) x)=0, \text { factor } \end{aligned}
solutions: $x=0$ and $x=2$
1) $x=0$, half its square is $(1 / 2) 0^{2}=0$. Hence $x$ and half its square are equal.
2) $x=2$, half its square is $(1 / 2) 2^{2}=2$. Hence $x$ and half its square are equal.
by Platinum (164,290 points)

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