Given: \(\lambda=3.4\), and \(x=6\)
Using the Poisson distribution formula:
\[
\begin{aligned}
&P(X=x)=\left(e^{-\lambda} \lambda^{x}\right) / x ! \\
&P(X=6)=\left(e^{-3.4} 3.4^{6}\right) / 6 ! \\
&P(X=6)=0.072
\end{aligned}
\]
Answer: The probability of function is \(7.2 \%\).