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arrow_back Solve the equation \(4 x^{2}-8 x-3=0\)

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Solve the equation \(4 x^{2}-8 x-3=0\)

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Best answer

Answer:
\[
x=1+\frac{\sqrt{7}}{2} \text { or } x=1-\frac{\sqrt{7}}{2}
\]


Explanation:
\(4 x^{2}-8 x-3=0\)
Identify the coefficients
\(a^{-4}, b=-8, c=-3\)
Substiture the values into the quadratic formula
\[
x=\frac{-(-8)+\sqrt{(-8)^{2}-4 \times 4 \times(-3)}}{2 \times 4}
\]

by Gold Status
(30,543 points)

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