arrow_back Solve the equation $4 x^{2}-8 x-3=0$

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Solve the equation $4 x^{2}-8 x-3=0$

$x=1+\frac{\sqrt{7}}{2} \text { or } x=1-\frac{\sqrt{7}}{2}$

Explanation:
$4 x^{2}-8 x-3=0$
Identify the coefficients
$a^{-4}, b=-8, c=-3$
Substiture the values into the quadratic formula
$x=\frac{-(-8)+\sqrt{(-8)^{2}-4 \times 4 \times(-3)}}{2 \times 4}$

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