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If \(\dfrac{d^{2} y}{d x^{2}}=10-3 x\), find \(\dfrac{d y}{d x}+c\)
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\(\begin{aligned} \frac{d y}{d x}=\int &(10-3 x) d x=\int 10 d x-\int 3 x d x \\ &=10 x-\left(\frac{3 x^{1+1}}{1+1}\right)+c \\ &=10 x-\left(\frac{3 x^{2}}{2}\right)+c \\ &=10 x-\frac{3}{2} x^{2}+c \end{aligned}\)
by Diamond (38,951 points)
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