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Evaluate $x^2+49=0$
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(1) Subtract 49 from both sides.
$x^{2}=-49$
(2) Take the square root of both sides.
$x=\pm \sqrt{-49}$
(3) Simplify $\sqrt{-49}$ to $\sqrt{49}$.
$x=\pm \sqrt{49} \imath$
(4) Since $7 \times 7=49$, the square root of 49 is 7 .
$x=\pm 7 \imath$
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