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In the diagram, A(6;-2), B(2,15) and C(-4;3) are the vertices of $\bigtriangleup{ABC}$. M is the endpoint of AB. N is a point on CA such that MN $\parallel$ BC.

  1. Determine the coordinates of M, the midpoint of AB
  2. Determine the gradient of line MN
  3. Hence, or otherwise, determine the equation of line MN, in the form $y=mc+c$
  4. Calculate, with reasons, the coordinates of point N
  5. If ABCD (in that order) is a parallologram, determine the coordinates of point D.




in Mathematics by Diamond (75,948 points) | 240 views

1 Answer

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1.M= ((6+2)/2 ; (-2+15)/2 )

  = (4; 13/2 )

2. Gradient MN=(15-3)/(2-(-4))

                      = 2

3. MN, y-13/2 = 2(x-4)

               y= 2x - 3/2
by Diamond (43,720 points)

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