For two events to be mutually exclusive, with event A and B, the probability of their union is the sum of the probabilities of the events.
P(A∪B)=P(A)+P(B)
0.28 is not = 0.7 + 0.4 = 1.10 , therefore A and B are not mutually exclusive, they can happen at same time.
Two events, A and B are independent if and only if:
P(A and B)=P(A)×P(B)
0.28 = 0.7 x 0.4 = 0.28 , therefore independent.