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Expand the sequence and find the value of the series: $\sum_{n=1}^{6}2^n$
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T1 = 2^1 = 2

T2 = 2^2 = 4

T3 = 2^3 = 8 , hence it is geometric series with r = 2

therefore value r sum = a(r^n -1)/(r-1)

= 2(2^6 - 1)/(2-1)

= 126
by Diamond (43,702 points)

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