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The distance, s metres, of a particle from a fixed point after t seconds $(t \ge 0)$ is given by the formula $s=\frac{4}{3}t^3-18t^2-144t+72$

1. Determine a formula for the velocity of the particle at t seconds
2. When the particle is at rest.

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velocity = displacement/time = ds/dt

1. $\dfrac{\text{ds}}{\text{dt}} = 4t^2 - 36t -144$

2. When particle is at rest, velocity = 0

Therefore $4t^2 - 36t -144 = 0$
by Gold Status (26,679 points)
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1) Determine the formula for the velocity of the particle at "t" seconds.

s = 4/3t^3 - 18t^2 -144t + 72

ds/dt = 4t^2 - 36t - 144

2) When the particle is at rest, velocity is equal to zero.

Velocity = 0 Therefore, 4t^2 - 36t - 144 = 0
by Wooden Status (469 points)

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