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Solve the equation $e^{\ln{4} + \ln{x}} = 1$
in MAT1581 by Diamond (40.2k points) | 13 views

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using the laws of exponents

 

$$e^{\ln{4}+\ln{x}}=1$$

$$e^{\ln{4x}}=e^{0}$$

Therefore

$$4x=1$$

which implies that

$$x=\dfrac{1}{4}$$

 

 

by Wooden (3.5k points)

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