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If $\log 5 = 0,7$, determine $\log_2 5$ without using a calculator
by Diamond (53,882 points) | 39 views

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10^0.7 =5

2^x = 5

hence, 2^x = 10^0.7

           xlog2 = log10^0.7

          xlog2 = 0.7

            x= 0.7/log2

therefore log 5, to base 2, is 0.7/log2
by Diamond (40,360 points)

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