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Given $f(x)=2\sin{x}$ and $g(x)=\cos{(x+30^{\circ})}$ for $x \in [0^{\circ}; 360^{\circ}]$

1. Draw the graphs of $f$ and $g$ on the same set of axes. Clearly show the intercepts with the axes as well as the turning points of the graphs.
2. Write down the amplitude of $f$ .
3. Determine the period of $g(x-60^{\circ})$
4. For which value(s) of $x$ is $g(x)<0$
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1. For f(x) = 2sinx draw the graph of sinx with amplitude 2, not 1.
for x and y-intercepts, let y = 0 and x = 0 respectively and solve to find the coordinates.
period = 360 degrees
minimum and maximum points will be at 2 and -2 respectively, substitute them to get corresponding y-values of coordinates..

For g(x) = cos(x + 30) draw the graph of cos x but shifted 30 degrees to the left, with amplitude 1.
for x and y-intercepts, let y = 0 and x = 0 respectively and solve to find the coordinates.
period = 360 degrees
minimum and maximum points will be at 1 and -1 respectively, substitute them to get corresponding y-values of coordinates.

2. amplitude of f is 2, coefficient of sin x

3. period of g(x -60) is 360 degrees

4. From the graph of g(x), check the values of x where the graph's values of y are less than zero.
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