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The circuit below consists of a 6 Ω and 15 Ω resistor connected in parallel and an unknown resistor R, in series. An ammeter, a high-resistance voltmeter, a closed switch and battery are connected, as shown. The resistance of the battery and wires can be ignored.
The total power dissipated in the parallel part of the circuit is 50 W.

1. Calculate the effective resistance of the parallel combination.
2. Calculate the potential difference across the resistors in parallel.
3. Calculate the current through resistor R.

in Grade 11 Physical Sciences by Silver Status (31.3k points) | 22 views

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1. The effective resistance of parallel combination

1/R = 1/R1 + 1/R2

1/R = 1/6 + 1/15

R = 4.29 ohms

2. Potential difference of resistors in parallel

P = V^2/R

50 = V^2/ 4.29

V = 14.65 volts

3. Current through resistor R

R = V/I

4.29 = 14.65/I

I = 3.41 A
by Wooden (2.3k points)
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