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A sphere has a charge of $-6.40 \times 10^-7$ coulomb.  Approximately how many electrons must be removed to make the sphere neutral?
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The charge on a single electron is -1.6 × 10^(-19) coulombs. The number that need to be removed to remove 6.4 × 10^(-7) coulombs of charge is therefore:

number of electrons = total charge / charge per electron

$=\dfrac{ 6.4 \times 10^{-7} }{1.6 \times 10^{-19}}$

$=\dfrac{6.4 \times 10 ^{-7-(-19)}}{1.6}$

$=4 \times 10^{-7+19}$

$= 4 \times 10 ^{ 12}$ electrons
by Wooden (1,126 points)
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