If the resistors are wired in series, find the equivalent resistance.

Question

A circuit contains two resistors: 20 Ω and 10 Ω

            a.) If the resistors are wired in series, find the equivalent resistance.

            b.) If the resistors are wired in parallel, find the equivalent resistance.

            c.) Which circuit would you construct if you wanted the smallest resistance?

Answer 1

a) Rq = R1 + R2

=20 + 10

Rq = 30 OHMS

b) 1 / Rq = 1/R1 + 1/R2

1/Rq = 1/20 + 1/10

1/Rq = 3/20 => Cross Multiply

Rq = 20/3 OHMS

c) I would use the parallel circuit because it has less/smallest resistance

Answer 2

a. Rt = R1 + R2

            = 20 + 10

            = 30 ohms

b. 1/Rt = 1/R1 + 1/R2

              =1/20 + 1/10

                =3/20

        Rt = 20/3

                =6.667 ohms

c. Parallel

Answer 3

a.) R eq = R1 + R2

             = 20 + 10

     R eq = 30ohms

 b.) 1/R eq = 1/R1 + 1/R2

                   = 1/20 + 1/10

                   = 1/20 +2/20

                   = 3/20

           20/3 = R eq

c.) I would construct the parallel circuit if I wanted the small resistance.

Answer 4

a:     Rt     = R1 + R2

                = 20Ω + 10Ω

                = 30Ω

b:    1/Rt     = 1/R1 + 1/R2

                   = 1/20 + 1/10

                    = (1+2)/20

                    = 3/20

         Rt        = 20/3

                    = 6.666 Ω

 

c:    Parralel circuit has lower resistance.

Answer 5

a)V=V1+V2

V=20+10

V=30 Ohms

b) 1/RT=1/R1+1/R2

1/RT=1/20+1/10

1/RT=1+2/20

1RT=3/20

RT=20/3 ohms