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A circuit contains two resistors: 20 Ω and 10 Ω

            a.) If the resistors are wired in series, find the equivalent resistance.

            b.) If the resistors are wired in parallel, find the equivalent resistance.

            c.) Which circuit would you construct if you wanted the smallest resistance?
in Random by Diamond (53,829 points) | 46 views

5 Answers

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a) Rq = R1 + R2

=20 + 10

Rq = 30 OHMS

b) 1 / Rq = 1/R1 + 1/R2

1/Rq = 1/20 + 1/10

1/Rq = 3/20 => Cross Multiply

Rq = 20/3 OHMS

c) I would use the parallel circuit because it has less/smallest resistance
by Wooden (1,126 points)
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a. Rt = R1 + R2

            = 20 + 10

            = 30 ohms

b. 1/Rt = 1/R1 + 1/R2

              =1/20 + 1/10

                =3/20

        Rt = 20/3

                =6.667 ohms

c. Parallel
by Wooden (361 points)
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a.) R eq = R1 + R2

             = 20 + 10

     R eq = 30ohms

 b.) 1/R eq = 1/R1 + 1/R2

                   = 1/20 + 1/10

                   = 1/20 +2/20

                   = 3/20

           20/3 = R eq

c.) I would construct the parallel circuit if I wanted the small resistance.
by Wooden (474 points)
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a:     Rt     = R1 + R2

                = 20Ω + 10Ω

                = 30Ω

b:    1/Rt     = 1/R1 + 1/R2

                   = 1/20 + 1/10

                    = (1+2)/20

                    = 3/20

         Rt        = 20/3

                    = 6.666 Ω

 

c:    Parralel circuit has lower resistance.
by Wooden (560 points)
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a)V=V1+V2

V=20+10

V=30 Ohms

b) 1/RT=1/R1+1/R2

1/RT=1/20+1/10

1/RT=1+2/20

1RT=3/20

RT=20/3 ohms
by Wooden (288 points)

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