Question

Two electrostatic point charges of +60.0 µC and +50.0 µC exert a repulsive force on each other of 175 N.  What is the distance between the two charges?

Answer 1

$F=\dfrac{KQ_1Q_2}{r^2}$

$r=\sqrt{ \dfrac{KQ_1Q_2}{F}}$

$=\dfrac{(9 \times10^9)(60 \times10^{-6})(50 \times10^{-6})}{175}$

$= 0.3928$ m