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A 4,000-kg car makes a turn with a velocity of 20 m/s.  If the centripetal force of the car is 600 Newtons, determine the radius of the turn.
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4 Answers

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m = 4000 kg     V = 20 m/s    Fc = 600N

Fc = mv² / r

r = mv² / Fc

= (4000)(20)² / 600

= 2666.67 m
by Wooden (786 points)
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r= mv^2/F

=(4.000)(20)^2/600

=2.667 m
by Wooden (2,549 points)
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F=mv^2/r

mv^2=fr

(4.000)(20)^2=600r

1600=600r divide both sides by 600 to find r

r=2.66m
by Wooden (233 points)
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m =4000kg v = 20 m/s F = 600N r =? r = mv^2/F = 4000(20)^2/600 = 2,667m
by Wooden (310 points)

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