MathsGee is free of annoying ads. We want to keep it like this. You can help with your DONATION

0 like 0 dislike
61 views
1. Determine the energy of a photon with a frequency of $6.10 \times 10^{14}$ Hz.
1. In joules

1. In electronvolts (eV): Recall that 1 eV = 1.6 x 10 -19J

edited | 61 views

1 like 0 dislike
a) E = hf

= (6.63x10^-34)(6.10x10^14)

= 4.04x10^-14 J

b) 4.04x10^-14 / 1.6x10^-19

= 2.525 eV
by Wooden (786 points)
selected by

0 like 0 dislike