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  1. Determine the energy of a photon with a frequency of $6.10 \times 10^{14}$ Hz.
    1. In joules

 

  1. In electronvolts (eV): Recall that 1 eV = 1.6 x 10 -19J
in Grade 12 Physical Sciences by Diamond (50,571 points)
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1 Answer

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Best answer
a) E = hf

    = (6.63x10^-34)(6.10x10^14)

    = 4.04x10^-14 J

b) 4.04x10^-14 / 1.6x10^-19

    = 2.525 eV
by Wooden (786 points)
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