Quality Learning Support For All
First time here? Checkout the FAQs!
x
MathsGee is Zero-Rated (You do not need data to access) on: Telkom |Dimension Data | Rain | MWEB

0 like 0 dislike
78 views
A light beam hits glass (refractive index = 1.52) at an angle of incidence of ${48}^{\circ}$. What is the angle of refraction?
in Physics by Diamond (81,178 points)
recategorized by | 78 views

1 Answer

1 like 0 dislike
Best answer
Using Snell's law,

$n_1\sin{x_1} = n_2\sin{x_2}$

$  1.52\sin{48^{\circ}} = 1\cdot \sin{x_2}$

$\sin{x_2} = \dfrac{1} {1.52\sin{48^{\circ}} } $

$x_2 = 62.29^{\circ} $ degrees angle of refraction.
by Diamond (44,188 points)
selected by

Related questions

0 like 0 dislike
1 answer
0 like 0 dislike
1 answer
asked Jun 1, 2020 in Physics by Joshua Mwanza Diamond (44,188 points) | 79 views
0 like 0 dislike
1 answer
asked Aug 28, 2019 in Physics by MathsGee Diamond (81,178 points) | 1,601 views

Join the MathsGee Answer Hub community and get study support for success - MathsGee Answer Hub provides answers to subject-specific educational questions for improved outcomes.



On MathsGee Answers, you can:


  1. Ask questions
  2. Answer questions
  3. Comment on Answers
  4. Vote on Questions and Answers
  5. Donate to your favourite users
  6. Create/Take Live Video Lessons

Posting on MathsGee


  1. Remember the human
  2. Behave like you would in real life
  3. Look for the original source of content
  4. Search for duplicates before posting
  5. Read the community's rules
MathsGee Tools

Math Worksheet Generator

Math Algebra Solver

Trigonometry Simulations

Vectors Simulations

Matrix Arithmetic Simulations

Matrix Transformations Simulations

Quadratic Equations Simulations

Probability & Statistics Simulations

PHET Simulations

Visual Statistics

MathsGee ZOOM | eBook